CHAPTER II/p2-TWO OPPOSITE HEMISPHERES OF MOON

TWO OPPOSITE H.S OF MOON

Moon is the only satellite to Earth. In human life, the Moon merges in poet, music and children’s daily dream.

Since 50^th of last century, human being had succeeded in researching the Moon, U.S scientists even launched in there and planned to build an outpost on it, their plan is still going on.  Nonetheless we don’t discuss about their plan, but we do discuss about another issue: the charges on Moon and their influence to the Earth.

We denote magnetic compositions contributed by Moon’s hemisphere the Δ4, Δ5 and Δ6 where Δ4 is for negative hemi-sphere influence, Δ5 is for positive hemi sphere; and Δ6 is for total charge contribution.

The following is charged Moon that depicted by NASA:

The ion wind from Sun is striking on Moon’s surface and energizing the electrons on there, as NASA’s argument, the direct result is to electrify the shined part positively. The highly energized electrons flock to settle on the dark side of the Moon where they lost their energy. That’s how the Moon surface is such illustrated in the Image 1/v. In order to clarify the Moon’s hemisphere effects on Earth, we set and solve the following problem.

1-Problem 1: The lunar hemisphere effect.

Under sunlight, the Moon is a charged or an electrified object. Suppose that the nature of object is neutral and so the positive charge on shined side is balanced against the negative charge on the dark side.

Conclusion for solution 1:

The opposite hemi-spheres of Moon induce magnetism on P(Houston). As seen in the figure 6/v above, Qb is nearer to Earth; by the inverse law of electric force, Qb can influence more than Qa.

Moon is considered as stationary during the Earth is rotating, so Moon’s magnetic vector is parallel with Earth’s rotation axis and consists of X and D compositions.

Qb might be negative which induces a contribution that heads to North, against current Earth’s magnetism.

The result of calculation (6.241*10^-23*Qb Tesla) is not too tiny because Qb is still unknown and varying at all the time. If we give Qb or Qa a certain figure such as 10 6 Coulombs, we may have B(hs), but we don’t do it now as our discussion is still going on.